1. WIKI教程
2. Java.util包
3. boolean removeLastOccurrence(Object o)

boolean removeLastOccurrence(Object o)

描述 (Description)

java.util.ArrayDeque.removeLastOccurrence(Object)方法删除此deque最后一次出现的指定element 。

声明 (Declaration)

以下是java.util.ArrayDeque.removeLastOccurrence(o)方法的声明

public boolean removeLastOccurrence(Object o)

参数 (Parameters)

o - 如果存在，将从此双端队列中删除最后一次出现的元素。

返回值 (Return Value)

如果deque包含指定的元素，则此方法返回true 。

异常 (Exception)

NA

例子 (Example)

以下示例显示了java.util.ArrayDeque.removeLastOccurrence（o）方法的用法。

package com.iowiki;
import java.util.ArrayDeque;
import java.util.Deque;
public class ArrayDequeDemo {
   public static void main(String[] args) {
      // create an empty array deque with an initial capacity
      Deque<Integer> deque = new ArrayDeque<Integer>(5);
      // use add() method to add elements in the deque
      deque.add(15);
      deque.add(20);
      deque.add(25);
      deque.add(20);
      // let us print all the elements available in deque
      for (Integer number : deque) {
         System.out.println("Number = " + number);
      }
      // this will remove last occurrence of element 20
      deque.removeLastOccurrence(20);
      System.out.println("Remaining Elements:");
      // let us print all the elements available in deque
      for (Integer number : deque) {
         System.out.println("Number = " + number);
      }
   }
}

让我们编译并运行上面的程序，这将产生以下结果 -

Number = 15
Number = 20
Number = 25
Number = 20
Remaining Elements:
Number = 15
Number = 20
Number = 25